They [2] gave the following result. (We state it here only in the case of genus one. ) THEOREM B. Let g(z) be a canonical product of genus one and having zeros ...
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SOME PROPERTIES OF CANONICAL PRODUCTS. OF FINITE GENUS. BY MASANOBU TSUZUKI. Introduction. Let f(z) be a canonical product of finite order ...
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Feb 7, 2011 ... then all the can be chosen to be the same, starting, e.g. from the minimal requirement that ; this is called the genus of the canonical product.
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Some properties of canonical products of genus zero with nega- tive zeros. If all the zeros of a canonical product h(z) are negative, it is clear that h(z) is ...
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Topics: Infinite products, canonical products, genus, order, Hadamard's The- orem, Reflection Principle, analytic continuation, branch point, harmonic func- tions.
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In an earlier paper1 1 proved the following result. THEOREM 1. If F(z) be of integral order p and if the genus of the canonical product f {z) be p=p, then log M( r, F) ...
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In this note I prove an inequality analogous to (1) for the class of canonical products of integral order p J5> 1 whose genus p is equal to p. The main result is the ...
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z | g r, and «(r) s j(r)+k(r); J,K are non-negative constants; 5(z, a,y,q) is the canonical product of genus q denned by s,w,,,. ft (i+^')P{ and. P(z, a, b, v, q) = S(z, a, y, ...
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Adjunction formula (algebraic geometry) - Wikipedia, the free ...
en.wikipedia.org/wiki/Adjunction_formula_(algebraic_geo...
en.wikipedia.org/wiki/Adjunction_formula_(algebraic_geometry)
The genus-degree formula for plane curves can be deduced from the ... equals the canonical class of C. This restriction is the same as the intersection product (d ... |
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It will be proved here that for the canonical product P with a genus p and negative zeros, (−1)p log P(r) ∈ ER[p,p+1] without any assumption on the distri- ...
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