Letf(z) be a meromorphic function of finite order. )X and genus q. We write g(f) =q, and, in general, denote by g(h) the genus of h(z). It is well known that the order ...
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MEROMORPHIC FUNCTIONS OF FINITE ORDER. S. M. SHAH. 1. Introduction. Let f(z) be an entire function of finite order p. If the genus p of the canonical ...
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To prove these theorems we establish the lemma: LEMMA. For any given meromorphic function (1) of genus s, let cl, c2, ... denote the totality of a,, a2, and bi, b2, ...
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Riemann–Roch theorem - Wikipedia, the free encyclopedia
en.wikipedia.org/wiki/Riemann%E2%80%93Roch_theorem
We start with a connected compact Riemann surface of genus g, and a fixed point P on ... A divisor of a global meromorphic function is called a principal divisor. |
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Riemann surface - Wikipedia, the free encyclopedia
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3 Holomorphic and meromorphic functions. 12 ... 2 The case of genus 1. 126 ... 9 Smooth points tangent spaces and the implicit function theorem. 36 ...
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GENUS OF A MEROMORPHIC FUNCTION. ALBERT EDREI1 AND S. M. SHAH2. 1. Introduction. Let/(z) be a meromorphic function of finite order. X and genus q ...
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Let G{z) be a canonical product of finite genus having only negative zeros. If its genus is sufficiently large, then. THEOREM 3. Let F(z) be a meromorphic function ...
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We prove that if n ≥ 4, a generic Riemann surface of genus 1 admits a meromorphic function (i.e., an analytic branched cover of IP. 1. ) of degree n such that ...
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We begin with a fixed compact Riemann surface M = Mg of genus g. A meromorphic function on M is, by definition, a holomorphic map f : M →P1 = C U { 叨}: ...
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