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Idempotence
An idempotent element of a ring is, by definition, an element that is idempotent for the ring's multiplication. More »
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planetmath.org/encyclopedia/Idempotent2.html
Dec 5, 2006 ... An element $x$ of a ring is called an idempotent element, or simply an idempotent if $x^2 = x$ . The set of idempotents of a ring can be partially ...
www.physicsforums.com/showthread.php?t=65173
idempotent elements Linear & Abstract Algebra discussion.
www.math.niu.edu/~beachy/abstract_algebra/study_guide/s... www.math.niu.edu/~beachy/abstract_algebra/study_guide/soln5.html
(c) Find all idempotent elements of R. Solution: By part (b), an element in R is either a unit or nilpotent. The only unit that is idempotent is the identity matrix (in a ...
www.math.umn.edu/~garrett/m/intro_algebra/s9.pdf
#1 Find all idempotent elements in Z/(17 • 19). For x to be an idempotent is that x satisfies x2 = x mod 17•19. By Sun Ze, this is equivalent to x2 = x mod 17 ...
www.mathreference.com/ring,nil.html
Math reference, nilpotent and idempotent elements.
math.stackexchange.com/questions/45747/how-many-idempot... math.stackexchange.com/questions/45747/how-many-idempotent-elements-does-the-ring-bf-z-n-contain
Jun 16, 2011 ... For a specif $n\in{\bf Z}_+$, which is not very large, say, $n=20$, one can calculate one by one to find that there are four idempotent elements: ...
www.math.ualberta.ca/people/Faculty/Sehgal/publications... www.math.ualberta.ca/people/Faculty/Sehgal/publications/014.pdf
Idempotent elements and ideals in group rings. 587. Another consequence of Lemma 4.2 is that if ZG is the group ring of a finitely generated nilpotent group then ...
www.proofwiki.org/wiki/Definition:Idempotent/Element
Jan 28, 2012 ... The element $x \in S$ is idempotent under the operation $\circ$ iff $x \circ x = x$. For example, $0$ is idempotent under the operation of ...
noether.uoregon.edu/~tingey/fall02/444/hw2.pdf
If ∗ is a binary operation on a set S, an element x is called idempotent for ∗ if x ∗ x = x. Prove that a group has exactly one idempotent element. Proof: Assume a ...
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